subtract of complex number as well as integer using operator overloading in a single program
Solution:
#include <iostream>using namespace std;
class sub
{
public:
int x;
int A,B;
int n=2; //n=1 for numbers and n=2 for imaginary num
void input1()
{
if(n==1)
{
cout<<"enter num";
cin>>A;
}
if(n==2)
{
cout<<"enter real and imaginary parts:";
cin>>A>>B;
}
}
sub operator -(sub a2)
{
sub temp;
temp.n=n;
if(n==1)
{
temp.A=A-a2.A;
}
if (n==2)
{
temp.A=A-a2.A;
temp.B=B-a2.B;
}
return temp;
}
void output1()
{
if(n==1)
{
cout<<"sub of two number:"<<A;
}
if(n==2)
{
cout<<"sub of two imaginary numbers:"<<A<<"+i"<<B;
}
}
};
int main()
{
sub a1,a2,result;
a1.input1();
a2.input1();
result=a1-a2;
result.output1();
return 0;
}
Output:
0 comments: